TSTP Solution File: SEV393^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEV393^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:53 EDT 2023
% Result : Theorem 3.68s 3.87s
% Output : Proof 3.68s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEV393^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n018.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Thu Aug 24 04:12:57 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.68/3.87 SZS status Theorem for theBenchmark.p
% 3.68/3.87 SZS output start Proof for theBenchmark.p
% 3.68/3.87 Clause #0 (by assumption #[]): Eq (Not ((Eq (fun Xz => Or (cR Xz) (cS Xz)) fun Xx => And (cR Xx) (cS Xx)) → ∀ (Xx : Iota), cR Xx → cS Xx)) True
% 3.68/3.87 Clause #1 (by clausification #[0]): Eq ((Eq (fun Xz => Or (cR Xz) (cS Xz)) fun Xx => And (cR Xx) (cS Xx)) → ∀ (Xx : Iota), cR Xx → cS Xx) False
% 3.68/3.87 Clause #2 (by clausification #[1]): Eq (Eq (fun Xz => Or (cR Xz) (cS Xz)) fun Xx => And (cR Xx) (cS Xx)) True
% 3.68/3.87 Clause #3 (by clausification #[1]): Eq (∀ (Xx : Iota), cR Xx → cS Xx) False
% 3.68/3.87 Clause #4 (by clausification #[2]): Eq (fun Xz => Or (cR Xz) (cS Xz)) fun Xx => And (cR Xx) (cS Xx)
% 3.68/3.87 Clause #5 (by argument congruence #[4]): ∀ (a : Iota), Eq ((fun Xz => Or (cR Xz) (cS Xz)) a) ((fun Xx => And (cR Xx) (cS Xx)) a)
% 3.68/3.87 Clause #6 (by clausification #[3]): ∀ (a : Iota), Eq (Not (cR (skS.0 0 a) → cS (skS.0 0 a))) True
% 3.68/3.87 Clause #7 (by clausification #[6]): ∀ (a : Iota), Eq (cR (skS.0 0 a) → cS (skS.0 0 a)) False
% 3.68/3.87 Clause #8 (by clausification #[7]): ∀ (a : Iota), Eq (cR (skS.0 0 a)) True
% 3.68/3.87 Clause #9 (by clausification #[7]): ∀ (a : Iota), Eq (cS (skS.0 0 a)) False
% 3.68/3.87 Clause #10 (by betaEtaReduce #[5]): ∀ (a : Iota), Eq (Or (cR a) (cS a)) (And (cR a) (cS a))
% 3.68/3.87 Clause #12 (by identity boolHoist #[10]): ∀ (a : Iota), Or (Eq (Or (cR a) False) (And (cR a) (cS a))) (Eq (cS a) True)
% 3.68/3.87 Clause #16 (by bool simp #[12]): ∀ (a : Iota), Or (Eq (cR a) (And (cR a) (cS a))) (Eq (cS a) True)
% 3.68/3.87 Clause #18 (by identity boolHoist #[16]): ∀ (a : Iota), Or (Eq (cS a) True) (Or (Eq (cR a) (And (cR a) False)) (Eq (cS a) True))
% 3.68/3.87 Clause #20 (by bool simp #[18]): ∀ (a : Iota), Or (Eq (cS a) True) (Or (Eq (cR a) False) (Eq (cS a) True))
% 3.68/3.87 Clause #21 (by eliminate duplicate literals #[20]): ∀ (a : Iota), Or (Eq (cS a) True) (Eq (cR a) False)
% 3.68/3.87 Clause #22 (by superposition #[21, 8]): ∀ (a : Iota), Or (Eq (cS (skS.0 0 a)) True) (Eq False True)
% 3.68/3.87 Clause #23 (by clausification #[22]): ∀ (a : Iota), Eq (cS (skS.0 0 a)) True
% 3.68/3.87 Clause #24 (by superposition #[23, 9]): Eq True False
% 3.68/3.87 Clause #26 (by clausification #[24]): False
% 3.68/3.87 SZS output end Proof for theBenchmark.p
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